26y^2-8y-184=0

Solution for 26y^2-8y-184=0 equation:

26y^2-8y-184=0

a = 26; b = -8; c = -184;
Δ = b2-4ac
Δ = -82-4·26·(-184)
Δ = 19200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{19200}=\sqrt{6400*3}=\sqrt{6400}*\sqrt{3}=80\sqrt{3}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-80\sqrt{3}}{2*26}=\frac{8-80\sqrt{3}}{52}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+80\sqrt{3}}{2*26}=\frac{8+80\sqrt{3}}{52}
$